LSA E Mech 2017-18

In the opening week of my Christmas Break I competed in a track race at the Providence Career and Technical Academy. The race took place on an indoor track that features straightaways of 45 meters and curves of 55 meters. The race that I competed in was the 3000 meter run. Below is footage that was taken approximately halfway through my race, with about six laps to run. I am the runner in first with the maroon kit. Note that the turn begins at the white pole to the right of me(picture below). Also note that I am wearing green racing spikes. The turn ends when I am at the painted green line(picture below). Video: It took me approximately 10.40 seconds to round the curve which makes my average velocity 5.28 meters/second. From this we can obtain my centripetal acceleration using the equation Ac=v^2/r. Note the curves radius is 17.5 meters.  Equation for Centripetal Acceleration:  Ac=5.28^2/17.5 Ac=5.28 m/s^2 Unlike many of the better indoor tracks, PCTA'

My brother came home for break, and we had some brother-sister bonding time while ice skating at the Boss Arena at UR. I decided to time him as he skated from one goal line to the other, requesting that he try to keep as constant a velocity as he could. Using the stopwatch on my phone, I recorded the time it took him to do my request: 9.1 seconds. After returning home, I looked up the standard measurements of an ice hockey rink to find how far he had skated. I have decided to use the international measurements of rinks instead of the North American so there are no conversions. The full length of the rink is 61 meters. From the boards to the goal line is 4 meters, multiplied by 2 is 8, then subtracted from 61 is 53. So my brother skated 53 meters in 9.1 seconds. Assuming he skated at constant velocity, I can now determine his velocity on the ice using the formula: v =Δx/t v = 53/9.1 v = 5.82 m/s I'm curious about the friction of the blades of his skates an

Friction and Skiing The purpose of this blog is to determine the coefficient of kinetic friction that the ground is imposing on the skis while going down a slope. Over winter break, I went skiing at Jimimy Peak. I determined all of the factors that were necessary to figure out the coefficient of friction for this trail that I was going down which is called Riptide.  Link to video:  https://youtu.be/ZSOnKHrBAM0 The givens are the: Force of gravity - mass * gravity *Initial Velocity - 9.332 m/s *Final Velocity - 13.088 m/s Acceleration - 0.942 m/s^2  Distance travelled - 44.68 m Gravity - 9.8 m/s Mass - kilograms / gravity ---> 49.89 / 9.8 = 5.09 kg (this number cancels out anyways) Angle - 11 degrees *The initial and final velocity were found with Logger Pro using the video taken.  This angle is at 11 degrees and was found by extending the lines that the slope makes and using a protractor to figure out the exact angle. Free Body Diagram: