Skip to main content

Momentum in a Collision Between Two Exercise Balls

Nikki Nappi
Period E

For my snow day blog, I decided to test the momentum of a collision between two exercise balls. I have always wanted to run at someone with an exercise ball, and this seemed like the perfect excuse to do it. So, I went to Walmart, bought two exercise balls, both of the same diameter, both weighing about 2 pounds, or 0.91 kg. I found this, since the box had no information about the weight of the ball, by first weighing myself without the ball, then weighing myself with the ball, and subtracting the difference, which was two pounds. Google converter then told me this was about 0.91 kg. However, I know that the weight of the ball is not the same as the mass of the ball. So I did some calculations.



Then, my mom and I ran at each other. I set up a tripod and took a video of the collision on my phone, and used logger pro to find the velocity of our balls before and after the collision. (Since the balls went flying out of our hands after the collision, I decided to exclude our masses from the mass in the momentum calculations, just to show that the mass of the ball stayed the same throughout the entire collision. Also, my mom refused to tell me her weight.) In logger pro, I measured the width of my walkway outside and marked one meter from one spot to the other. I then put this into logger pro and began plotting points from the center of the ball.



My mom's ball before the collision -
Velocity : 0.4028 m/s
Momentum : 0.037 kg m/s
p = mv
p = 0.0929 kg * 0.4028 m/s
p = 0.037 kg m/s




My ball before the collision -
Velocity : -0.688 m/s (since I was running to the left, it is actually positive )
Momentum : 0.0639 kg m/s
p = mv
p = 0.0929 * -(-0.688)
p = 0.0639 kg m/s


My mom's ball after the collision -
Velocity : -0.5565 m/s (since it went to left, it will actually be positive)
Momentum :  0.51699 kg m/s
p = mv
p = 0.0929 kg * -(-0.5565 m/s)
p = 0.51699 kg m/s


My ball after the collision -
Velocity : 0.596 m/s
Momentum : 0.055 kg m/s
p = mv
p = 0.0929 kg * 0.596 m/s
p = 0.055 kg m/s

While this collision appears to be an inelastic collision, I wanted to confirm this information. In an inelastic collision, we know kinetic energy is not conserved. We could check if this collision was an inelastic collision using the formula Einitial = Efinal for both balls. If it is an inelastic collision, like I suspect, this equation will not be true. Since the balls went straight up after, the final energy is potential energy. This requires a height, which was very hard to measure exactly in this situation, so I am going to take an educated, VERY approximated, guess about the height of the ball. 

In this picture, which is about the peak height of the ball, the balls appear to be double my height in the air. I am 5'4, so the ball's height is ABOUT 10 feet 8 inches in the air. This is about 3.25 meters. 

KE = PE 
(1/2 mv^2) + (1/2 mv^2) = 2 *(mgh)  
(1/2 *  0.0929 *0.688 ^2) + (1/2 * 0.0929 * 0.4028 ^2)  = 2 * 0.0929 * 9.8 * 3.25 
0.02199  + 0.0075 = 2 * 2.958 
0.0295 J = 5.916 J 

This statement is not true, proving this collision to be an inelastic collision. There are a lot of areas where this could have gone wrong, including the measurement of the balls height and the fact that the balls hit me and my mom at different points, which affected the measurement of the velocity in logger pro. However, the difference in energy is so vast that even with these errors, this collision can still be proven to be an elastic collision. 

As we learned in class, momentum is conserved in this collision, but energy is not. This energy was lost through sound, by pushing me and my mom back when we collided, possibly friction between the balls, and in more areas. 

If our velocities were increased and we ran faster at one another, the balls would have gone higher into the air, and we most likely would have been pushed back further, maybe even being knocked on to the ground. My brother and I tested this theory afterwards, running almost full speed at one another. He got knocked down and the balls went flying in opposite directions, mine going as far as into the street, proving this theory. 



Comments

Popular posts from this blog

Physics of Black Holes...Or Lack Thereof

Isabella Jacavone To comprehend how the universe works, we must dwell into the most basic building blocks of existence; matter, energy, space, and time. NASA's  Physics of the Cosmos program involves cosmology, astrophysics, and fundamental physics intended to answer questions about the elusiveness of complex concepts such as black holes, neutron stars, dark energy, and gravitational waves. In this blog post, I'd like to elaborate on a subject that is very intriguing  to me; Black holes. And more specifically, what would happen if we got near one. A black hole is anything but a hole, but rather an immense amount of matter compacted into an extremely small area. A black hole is caused when, hypothetically, a star four times more massive than our sun collapses into a sphere no bigger than 600 square km. To put that in perspective, that's about the size of New York City. B lack holes were predicted by Einstein's theory of general relativity, which showed that when a...

Aerodynamics of a Golf Ball

One may wonder how a small golf ball can travel at incredibly high speeds for such long distances.  While the swing of the club is a major component, the structure of the golf ball is quite important.  Unlike a baseball or tennis ball, a golf ball has dimples all over it (usually 336 dimples).  These dimples allow the golf ball to travel without facing much air resistance.  This diagram shows how air travels around the golf ball. The dimples on the golf ball also prevent drag that would occur in the wake region, resulting in further distance.  Also due to the contact with the club during the swing, the golf ball has backspin during its entire flight.  This diagram shows the motion of the golf ball mid flight with the lift force of F. There are hundreds of different types of golf balls that a player can choose.  Some show little affect to a player's game while others can alter their performance completely.  Personally, I prefer Callaway Supers...

What Would Happen if Everyone in the World Jumped at Once?

Hypothetical and far out questions are what create great physicists and allow for us to discover and test things that have never been thought of before. Even as kids, we let our minds wander and ask questions that we never knew could be proved or disproved by physics. One question that I, as a young questioning child, and many other highly regarded physicists ask is simple; what would happen if every single person got together and jumped at once? This situation is completely unlikely to ever happen, so the only way we could ever know what would happen is through physics. Okay, so lets set the scene. Everyone, all 7 billion people, could fit into an area the size of Rhode Island, so lets assume that everyone did  travel to the smallest state in the US.  Finally, in unison, all 7 billion people jump. The push against the earth doesn't affect the earth at all, considering the Earth outweighs everyone by a factor of a mere 10 trillion. Even if the Earth were rigid and responde...